Description
Get a octal number from user and find the corresponding decimal number.
Input
10
Output
8
C Program
#include<stdio.h>
#include<math.h>
int DOConvert(long long num)
{
int i = 0, dec = 0;
int base = 8;
while (num!=0)
{
int digit = num % 10;
dec += digit * pow(base, i);
num /= 10;
i++;
}
return dec;
}
int main()
{
long long oct;
printf("Enter an octal number: ");
scanf("%lld", &oct);
printf("%lld", DOConvert(oct));
return 0;
}
C++ Program
#include <iostream>
#include<math.h>
using namespace std;
int DOConvert(long long num)
{
int i = 0, dec = 0;
int base = 8;
while (num!=0)
{
int digit = num % 10;
dec += digit * pow(base, i);
num /= 10;
i++;
}
return dec;
}
int main()
{
long long oct;
printf("Enter an octal number: ");
scanf("%lld", &oct);
printf("%lld", DOConvert(oct));
return 0;
}
Java Program
import java.util.Scanner;
import java.io.*;
class Main {
static int ODConvert(int n)
{
int num = n;
int dec = 0;
int base = 1;
int temp = num;
while (temp > 0) {
int rem = temp % 10;
temp = temp / 10;
dec += rem * base;
base = base * 8;
}
return dec;
}
public static void main(String[] args)
{
Scanner sc = new Scanner(System.in);
System.out.print("Enter an octal number: ");
int num = sc.nextInt();
System.out.println(ODConvert(num));
}
}
Python Program
def ODConvert(num):
dec = 0
base = 1
while num:
rem = num % 10
num = int(num / 10)
dec += rem * base
base = base * 8
return dec
octal = int(input("Enter an octal value: "))
print(ODConvert(octal))
