Description

Get the number of rows from the user and print the palindromic pattern as given below.

Input

3

Output

    1

  121

12321

C Program

#include<stdio.h>

int main()

{

    int rows;

    printf("Enter the row number:");

    scanf("%d",&rows);

    for(int i=0;i<=rows;i++)

    {

        for(int k=i;k<=rows;k++)

        printf(" ");

        for(int j=1;j<=i;j++)

        printf("%d",j);

        for(int j=i-1;j>0;j--)

        printf("%d",j);

    printf("\n");

    }

}

C++ Program

#include <iostream>

using namespace std;

int main()

{

    int rows;

    cout<<"Enter the row number: ";

    cin>>rows;

    for(int i=0;i<=rows;i++)

    {

        for(int k=i;k<=rows;k++)

        cout<<" ";

        for(int j=1;j<=i;j++)

        cout<<j;

        for(int j=i-1;j>0;j--)

        cout<<j;

    cout<<"\n";

    }

}

Java

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

Scanner sc = new Scanner(System.in);

System.out.print("Enter the number of rows: ");

int rows = sc.nextInt();

for(int i=0;i<=rows;i++)

        {

            for(int k=i;k<=rows;k++)

            System.out.print(" ");

            for(int j=1;j<=i;j++)

            System.out.print(j);

            for(int j=i-1;j>0;j--)

            System.out.print(j);

        System.out.println();

        }

}

}

Python

def palindrome(rows):

    for i in range(0,rows+1):

        for j in range(i,rows+1):

                print(" ",end=" ")

        for j in range(1,i+1):

            print(j,end=" ")

        for j in range(i-1,0,-1):

            print(j,end=" ")

        print()

rows=int(input("Enter the number of rows :"))

palindrome(rows)