# Write Program to find number of even and odd elements in an array

09 June 2022

Write Program to find number of even and odd elements in an array

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# Description

Get an array as input from the user and then count the number of even and odd elements present in the array.

Input

Enter size of array

4

Enter the elements:

1 3 4 5

Output

Number of even elements: 1

Number of odd elements: 3

C Program

#include<stdio.h>

int main(){

int n;

int arr[n];

printf("Enter the size of array elements: ");

scanf("%d",&n);

printf("Enter the array elements: ");

for(int i=0;i<n;i++)

scanf("%d",&arr[i]);

int even=0, odd=0;

for(int i=0; i<n; i++){

if(arr[i]%2==0)

even++;

else

odd++;

}

printf("Number of even elements: %d \nNumber of odd elements: %d", even, odd);

}

C++ Program

#include<iostream>

using namespace std;

int main(){

int n;

cout<<"Enter the size of array elements: ";

cin>>n;

int arr[n];

cout<<"Enter the array elements: ";

for(int i=0;i<n;i++)

cin>>arr[i];

int even=0, odd=0;

for(int i=0; i<n; i++){

if(arr[i]%2==0)

even++;

else

odd++;

}

cout<<"Number of even elements: "<<even<< "\nNumber of odd elements: "<<odd;

}

Java Program

import java.util.Scanner;

class Main{

public static void main (String[] args)

{

int n;

Scanner sc = new Scanner(System.in);

System.out.println("Enter the size of the array: ");

n = sc.nextInt();

int[]arr = new int[n];

System.out.println("Enter the array elements: ");

for(int i = 0; i < n; i++)

{

arr[i] = sc.nextInt();

}

int even = 0, odd = 0;

for(int i=0; i<n; i++){

if((arr[i] % 2 )== 0)

even += 1;

else

odd += 1;

}

System.out.println("Number of even elements: "+ even);

System.out.println("Number of odd elements: "+ odd);

}

}

Python Program

n = int(input("Enter size of array: "))

arr = []

print("Enter array elements: ")

for i in range(0,n):

temp = int(input())

arr.append(temp)

even = 0

odd = 0

for i in range(0, n):

if arr[i]%2==0 :

even += 1

else:

odd += 1

print("Number of even elements: ",even )

print("Number of odd elements: ",odd)

If you are from 2023 batch student, Join our Telegram group for placement preparation and coming placement drive updates : https://t.me/talentbattle2023