Write Program to find the array type

09 June 2022

Write Program to find the array type


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Description

Get an array as input from the user and check the type of the array, whether it is odd, even or mixed type.

Input

Enter size of array:

3

Enter elements

1 3 5

Output

Odd

 

C Program

#include<stdio.h>

int main()

{

int n;

printf("Enter the size of the array: ");

scanf("%d",&n);

int arr[n];

int i;

int o=0, e=0;

printf("Enter the array elements: ");

for(i = 0; i < n; i++)

{

scanf("%d",&arr[i]);

}

for(i = 0; i < n; i++)

{

if(arr[i] % 2 == 1)

o++;

if(arr[i] % 2 == 0)

e++;

}

if(o == n)

printf("Odd");

else if(e == n)

printf("Even");

else

printf("Mixed");

return 0;

}

 

C++ Program

#include<iostream>

using namespace std;

int main()

{

int n;

cout<<"Enter the size of the array: ";

cin>>n;

int arr[n];

int i;

int o=0, e=0;

cout<<"Enter the array elements: ";

for(i = 0; i < n; i++)

{

cin>>arr[i];

}

for(i = 0; i < n; i++)

{

if(arr[i] % 2 == 1)

o++;

if(arr[i] % 2 == 0)

e++;

}

if(o == n)

cout<<"Odd";

else if(e == n)

cout<<"Even";

else

cout<<"Mixed";

return 0;

}

 

Java Program

import java.util.*;

public class Main

{

public static void main(String[] args)

{

int n;

Scanner sc = new Scanner(System.in);

System.out.println("Enter the size of the array: ");

n = sc.nextInt();

int[]arr = new int[n];

System.out.println("Enter the array elements: ");

for(int i = 0; i < n; i++)

{

arr[i] = sc.nextInt();

}

int o =0, e = 0;

for(int i = 0; i < n; i++)

{

if(arr[i] % 2 == 1)

o++;

else

e++;

}

if(o == n)

System.out.print("Odd");

else if(e == n)

System.out.print("Even");

else

System.out.print("Mixed");

 

}

}

 

Python Program

n = int(input("Enter size of array: "))

arr = []

print("Enter array elements: ")

for i in range(0,n):

                temp = int(input())

                arr.append(temp)

o = 0

e = 0

for i in range(0,n):

                if(arr[i] % 2 == 1):

                                o = o + 1

                else:

                                e = e + 1

if(o == n):

                print("Odd")

elif(e == n):

                print("Even")

else:

                print("Mixed");


If you are from 2023 batch student, Join our Telegram group for placement preparation and coming placement drive updates : https://t.me/talentbattle2023
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