DXC Technology Quantitative Ability Questions
Q1) Arrange the following in ascending order:
2/15, 18/29, 7/18, 10/87.
A. 7/18 < 2/15 < 18/29 < 10/87
B. 10/87 < 7/18 < 2/15 < 18/29
C. 10/87 < 2/15 < 7/18 < 18/29
D. 18/29 < 10/87 < 2/15 < 7/18
Answer : Option C
Solution : The terms in the required order are 10/87, 2/15, 7/18, 18/29.
To arrange the terms from lowest to greatest, we will have to convert them into like terms.
So, we will find the LCM of the numbers' denominators.
The common and smallest multiple of 15, 29, 18, and 87=2×3×3×5×29
=2610
The terms will change as follows-
2×174/15×174=348/2610
18×90/29×90=1620/2610
7×145/18×145=1015/2610
10×30/87×30=300/2610
We will now compare the numerators of these numbers and arrange them accordingly.
The arrangement becomes: 300/2610, 348/2610, 1015/2610, 1620/2610
= 10/87, 2/15, 7/18, 18/29
Therefore, the terms in the required order are 10/87, 2/15, 7/18, 18/29.
Option C.
Q2) Find the L.C.M. of 26 * 32 * 5 * 7, 23 * 35 * 7 and 2 * 34 * 5.
A. 26 * 35 * 7
B. 26 * 35 * 5 * 7
C. 26 * 35 * 5
D. 26 * 35
Answer : Option B
Solution:
Q3) The value of log8(1/4096) is
A. -5
B. -2
C. -4
D. -3
Answer : Option C
Solution:
Formula:
logb(x) = y, if by = x
Input:
x = 1/4096 = 8-4
b = 8
Solution:
y = log8 (1/4096)
= log8 8-4
= -4 log8 8 = -4 x 1
log8 4096 = -4
Option C
Q4) If the G.C.D. of x2 + (p - 1) and x2 + px + (p - 1) is x - 1, then the value of p is?
A. 2
B. 3
C. 4
D. 5
Answer : Option B
Solution:
We all know that the GCD of two polynomials means that it is a common factor of both the polynomials.
Here we are given: GCD = x+1
this means that (x+1) is a factor of both the polynomials.
i.e. x = -1 is a zero of both the polynomial.
This implies on putting x=-1 in polynomial equation x² - px – 4
we have polynomial equation will be = zero.
x² - px - 4 = 0 at x = -1
1 - (-1)p - 4 = 0
1 + p - 4 = 0
p = 3
similarly, on putting x = -1 in the second polynomial and equating it equal to zero, we will have p = 3
Q5) A bag contains coins of Re. 1, Rs. 2 and Rs. 5 in the ratio of 4:8:5. The total amount in the bag is Rs. 90. The total number of Rs. 5 coins is
A. 15
B. 10
C. 8
D. 16
Answer : Option B
Solution :
The given ratio is 4 : 8 : 5
Let the number of 1 rupee coin is 4x, number of 2-rupee coin is 8x and number of 5-rupee coin is 5x
Number of coins = 4x + 8x + 5x = 17x
Total amount = 1 * 4x + 2*8x + 5*5x = 90 (given)
45x = 90
X = 2
So, the number of 5-rupee coins is 5x = 5*2 = 10
Option B.
Q6) If LCM and HCF of two numbers are 234 and 13 respectively, then the smallest factor of the product of the two numbers is:
A.2
B.3
C.4
D.5
Answer - Option A
Solution :
Given that LCM and HCF of two numbers are 234 and 13 respectively here we need to find smallest factor of the product of 2 numbers
As we know that the product of LCM and HCF of two numbers is equals to product of the two numbers
then the product of 2 numbers = LCM × HCF = 234 × 13 = 3042
here the smallest factor of 3042 = 2
option A.
Q7) A restaurant prepares 22 litres of a mixture that contains 25% of orange essence and the remaining quantity as water. If 3 litres of a water is mixed in this mixture, what will be the percentage of orange essence in the new mixture?
A.34%
B.4%
C.12%
D.22%
Answer - Option D
Solution :
22 litres of a mixture that contains 25% of orange essence and the remaining quantity is water.
Therefore, orange essence in 22 litres of a mixture = 25% of 22 = 5.5 ltres
3litres of water is added to the mixture
Therefore, total mixture = 22 + 3 = 25 litres
The percentage of orange essence now in the mixture = ( 5.5/25 )* 100 = 22%
Option D
Q8) Shalom offered to sell his ancestral house for Rs. 18,400. If he had charged 10% less, he would have made a profit of 20%. What is the actual cost of the house?
A.Rs.15,800
B.Rs.14,500
C.Rs.13,800
D.Rs.12,500
Answer - Option C
Solution : new SP=18400-10% of 18400=16560
Let CP=x
then x + 20% of x=16560
x=13800
therefore actual cost=13800
Option C
Q9) Parul is one-fifth the age of her mother was 15 years ago and Parul’s brother is three-fifth the age his mother was 10 years ago. If the sum of Parul and her brother’s ages is 31, then how old is Parul’s mother?
A.50
B.40
C.35
D.60
Answer - Option A
Solution :
Let Sony's mother's age be 'x'.
Now the conditions given for both of their ages related to their mom is
1/5(x-15) + 3/5(x-10) = 31
x-15 + 3x-30 = 1554
x-45 = 155
4x = 200
x = 50
So, Mother's age = 50.
Option A
Q10) Write √1008 as a mixed surd.
A.12 √7
B.7 √14
C.7 √12
D.14 √7
Answer - Option A
Solution :
Q11) A company makes a mixture which contains 2% alcohol. If 10 litres of alcohol is added to the mixture, then the concentration increases to 5%. What is the approx. quantity of the mixture?
A.316
B.315
C.320
D.300
Answer - Option A
Solution :
Let in the mixture of x litres, quantity of alcohol= (2/100) *x=x/50 litres.
When 10 litres of alcohol are added
Quantity of mixture= (x+10) litres and
Quantity of alcohol=10+ x/50 litres.
So % of alcohol in new mixture= (10 + x/50)/(x+10) = 5/100
x= 950/3= 316.66 ~ 316 litres
Q12) 20 men can do a job in 10 days, working 8 hours a day. If women are 33.33% more efficient than men, how many women will it take to finish the same job in 10 days, working 6 hours a day?
A.10
B.12
C.15
D.20
Answer - Option D
Solution :
Total work = no. of men * efficiency of men * no. of days * no. of hours a day
Let efficiency of men be = X, women = x + 33.33% of x = 4X/3
Total work = 20*x * 10 * 8 = 1600X units
In the case of women
Equating total work
1600 x = no. of women * 4x/3 * 10 * 6
No. of women = 20
Q13) Find the ratio of distances covered by a car and a cyclist when it is given that the car moves for 1.5 hours at 30 kmph and the cyclist moves for 1 hour at 25 kmph?
A.6:5
B.9:5
C.3:2
D.5:1
Answer - Option B
Solution :
Distance covered by car = 1.5 * 30 = 45km
Distance covered by cycle = 1 * 25 = 25 km
Ratio of distance = 45: 25 = 9: 5
Q14) A written exam consists of 6 questions with the answer options as yes/ no/ none. In how many ways can the examinees select the answers?
A. 6P3 ways
B. 6C3 ways
C. 3C1 * 3C1 * 3C1 * 3C1 * 3C1.
D. (3C1)6
Answer - Option D
Solution :
No. of ways to select answer for the 1st question = 3c1 out of (yes, no or none one answer should be selected)
Similarly, every question has 3 options
No. of ways of answering = 3c1 * 3c1 * 3c1 *3c1*3c1 *3c1 = (3c1)6
Q15) The light from a laser beam travels at a speed of 3,00,000,000 meters per second. How far can it be seen within 20 nano seconds, assuming that there is no obstruction in between? (20 nano seconds=20?10-9 seconds)
A. 3 m
B. 20 m
C. 6 m
D. 0..6 m
Answer - Option C
Solution :
Given that we are working with different units we need to do some conversions.
v=300000000m/s
t=20nanoseconds = 20 *10 −9 seconds
Distance travelled by the beam = V * T
=3×10 8 × 20 *10 −9
=6m
Q16) Supremo Coal Limited mined 8 1/3 tons of coal on Tuesday, 5 ¾ tons of coal on Monday and 9 ½ tons of coal on Wednesday. If the goal is to mine 30 tons of coal this week then how many more tons of coal need to be
A.23.59 tons
B.7.56 tons
C.6.89 tons
D.6.41 tons
Answer - Option C
Solution :
Q17) The sum of the squares of 3 numbers is 170, while the sum of their products taken two at a time is 157. What is the sum of the numbers?
A.20
B.22
C.24
D.28
Answer - Option B
Solution:
Q18) The tremors of the earthquake were felt at intervals of 15 seconds. The first tremor was felt at 08:54:57 am and the last tremor was felt at 10:45:112 am. How many times were the tremors felt?
A.484
B.485
C.441
D.525
Answer - Option C
Solution :
Difference of times = 10:45:12 - 8:54:57 = 9:104:72 - 8:54:57 = 1:50 :15 = 3600 + 3000 + 15 = 6615 seconds.
Now tremors are felt at the intervals of 15 seconds.
Total = 6615/15 = 441
Option C
Q19) A flower seller purchases roses at Rs. 96 a dozen and sells them at Rs. 10 per flower. What is profit percent of the flower seller?
A.40%
B.20%
C.25%
D.15%
Answer - Option C
Solution :
Let us find the price of one flower
The cost of twelve flowers = Rs. 96
The cost of one flower = 96/12
∴ The cost of one flower = Rs. 8
Let us calculate the profit
The selling cost of each flower = Rs. 10
∴ Profit on each flower selling = Rs. 10 - Rs. 8 = Rs. 2
Let us determine the profit percentage
Profit Percentage = (2/8) *100 = 25%
Option C
Q20) A train travelling at 250 kmph overtakes a cyclist who is travelling at 10 kmph in 45 seconds. What is the length of the train in meter?
A.3,000 m
B.5,400 m
C.6,000 m
D.10,800 m
Answer - Option A
Solution :
Speed of the Train= 250 kmph
Speed of the cycle = 10kmph
The train overtakes the cyclist who travels in 45 secs with a speed of 10 kmph
Now Relative speed= 250-10 = 240 kmph
Finding the length of the train
Then the Relative speed of the cyclist and the train = 240
The length of the train = (240*5*45)/18 = 3000 m
Option A
