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Program to find Sum of N natural numbers

06 May 2024

Description about Program to find Sum of N natural numbers

Get the input from the user for the value of n and then find the sum of first n natural numbers.

e.g.  let the n value = 5

then first 5 natural numbers are 1,2,3,4,5 for which we need to find the sum

Therefore sum of first 5 natural numbers is 1+2+3+4+5 = 15

Input

4

Output

10

 

C Program to find Sum of N natural numbers

 Method 1

#include <stdio.h>

int main()

{

    int num,sum=0;

    printf("Enter the number");

    scanf("%d",&num);

    for(int i=1;i<=num;i++)

        sum=sum+i;

    printf("%d",sum);

    return 0;

}

 

 Method 2

#include<stdio.h>

int Sum(int n)

{

    if (n!=0)

    return n + Sum(n-1);

    else

    return 0;

}

int main()

{

    int num,sum=0;

    printf("Enter the number: ");

    scanf("%d",&num);

    sum=Sum(num);

    printf("%d",sum);

    return 0;

}

 

C++ Program to find Sum of N natural numbers

Method 1

#include <iostream>

using namespace std;

int main()

{

    int num,sum=0;

    cout<<"Enter the number: ";

    cin>>num;

    for(int i=1;i<=num;i++)

        sum=sum+i;

    cout<<sum;

    return 0;

}

 

Method 2

#include <iostream>

using namespace std;

int Sum(int n)

{

    if (n!=0)

    return n + Sum(n-1);

    else

    return 0;

}

int main()

{

    int num,sum=0;

    cout<<"Enter the number: ";

    cin>>num;

    cout<<Sum(num);

    return 0;

}

 

Java Program to find Sum of N natural numbers

import java.util.Scanner;

public class Main

{

                public static void main(String[] args) {

                                Scanner sc = new Scanner(System.in);

                                System.out.print("Enter a number: ");                                                  

                                int num = sc.nextInt();

                                int sum= 0;

                                for(int i=0;i<=num;i++)

                                                sum = sum + i;

                                System.out.print(sum);

                }

}

 

Python Program to find Sum of N natural numbers

Method 1

num=int(input("Enter a number: "))

Sum=0

for i in range(1,num+1):

    Sum=Sum+i

print(Sum)

 

Method 2

def Sum(num):

    if num!=0:

        return num + Sum(num-1)

    else:

        return 0

num=int(input("Enter a number: "))

value=Sum(num)

print(value)

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