Description
Get an input number from user and check whether the given number is an Armstrong number or not.
E.g. Let the number be 1634,
Here 1^4 + 6^4 + 3 ^4 + 4^4 = 1634
Therefore, this is an Armstrong number
Input
153
Output
Armstrong number
Input
121
Output
Not an Armstrong number
C Program
#include <stdio.h>
#include<math.h>
int main()
{
int num, copy, rem, result = 0, n = 0 ;
printf("Enter a number: ");
scanf("%d", &num);
copy = num;
while (num != 0)
{
num /= 10;
n++;
}
num = copy;
while (num != 0)
{
rem = num%10;
result += pow(rem, n);
num /= 10;
}
if(result == copy)
printf("Armstrong number");
else
printf("Not an Armstrong number");
return 0;
}
C++ Program
#include <iostream>
#include<math.h>
using namespace std;
int main()
{
int num, copy, rem, result = 0, n = 0 ;
cout<<"Enter a number: ";
cin>>num;
copy = num;
while (num != 0)
{
num /= 10;
n++;
}
num = copy;
while (num != 0)
{
rem = num%10;
result += pow(rem, n);
num /= 10;
}
if(result == copy)
cout<<"Armstrong number";
else
cout<<"Not an Armstrong number";
return 0;
}
Java
import java.util.Scanner;
public class Main
{
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.print("Enter a number : ");
int num = sc.nextInt();
int copy = num;
int result=0;
int n=0;
int rem;
while (num != 0)
{
num /= 10;
n++;
}
num = copy;
while (num != 0)
{
rem = num%10;
int mul=1;
for(int i=1;i<=n;i++) {
mul=mul*rem;
}
result=result+mul;
num /= 10;
}
if(result==copy)
System.out.println("Armstrong Number");
else
System.out.println("Not Armstrong number");
}
}
Python
import math
num=int(input("Enter a number: "))
value = [int(d) for d in str(num)]
result = 0
for i in range(0, len(value)):
result = result + math.pow(value[i], len(value))
if result==num:
print("Armstrong number")
else:
print("Not an armstrong number")
