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Program to identify if the number is Perfect number or not

06 May 2024

Description about the Program to identify if the number is Perfect number or not

Get the input from the user and check whether that number is a perfect number or not.

E.g. Let number is 28, factors of 28 are 1,2,4,7,14. Now the sum of all these factors are 28 itself.

Input

28

Output

Perfect Number

Input

4

Output

Not a perfect number

C Program to identify if the number is Perfect number or not???????

Method 1

#include <stdio.h>

int main()

{

    int i,num,sum=0;

    printf("Enter a number: ");

    scanf("%d",&num);

    for(i=1;i<num;i++)

    {

        if(num%i==0)

        sum=sum+i;

    }

    if(num==sum)

    printf("Perfect number");

    else

    printf("Not a perfect number");

    return 0;

}

Method 2

#include <stdio.h>

#include<math.h>

int main()

{

    int i,num,sum=0;

    printf("Enter a number: ");

    scanf("%d",&num);

    for(i=1;i<=sqrt(num);i++)

    {

        if (num%i==0)

        {

            if(i==1)

                sum=sum+i;

            else if(i==num/i)

                sum=sum+i;

            else

                sum=sum+i+num/i;

        }

    }

    if(num==sum)

    printf("Perfect number");

    else

    printf("Not a perfect number");

    return 0;

}

C++ Program to identify if the number is Perfect number or not???????

Method 1

#include <iostream>

using namespace std;

int main()

{

    int i,num,sum=0;

    cout<<"Enter a number: ";

    cin>>num;

    for(i=1;i<num;i++)

    {

        if(num%i==0)

        sum=sum+i;

    }

    if(num==sum)

    cout<<"Perfect number";

    else

    cout<<"Not a perfect number";

    return 0;

}

Method 2

#include <iostream>

#include<math.h>

using namespace std;

int main()

{

    int i,num,sum=0;

    cout<<"Enter a number: ";

    cin>>num;

    for(i=1;i<=sqrt(num);i++)

    {

        if (num%i==0)

        {

            if(i==1)

                sum=sum+i;

            else if(i==num/i)

                sum=sum+i;

            else

                sum=sum+i+num/i;

        }

    }

    if(num==sum)

    cout<<"Perfect number";

    else

    cout<<"Not a perfect number";

    return 0;

}

Java Program to identify if the number is Perfect number or not

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

Scanner sc=new Scanner(System.in);

System.out.print("Enter a number: ");

int num=sc.nextInt();

int sum=0;

for(int i=1;i<num;i++)

{

if(num%i==0)

sum=sum+i;

}

if(sum==num)

System.out.println("Perfect Number");

else

System.out.println("Not an Perfect Number");

}

}

Python Program to identify if the number is Perfect number or not

num=int(input("Enter a number: "))

Sum=0

for i in range(1,num):

    if num%i==0:

        Sum=Sum+i

if(Sum==num):

    print("Perfect Number")

else:

    print("Not a perfect number")

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