# Program to identify if the number is Perfect number or not

17 May 2023

Write a program to identify if the number is Perfect number or not

## Description about the Program to identify if the number is Perfect number or not

Get the input from the user and check whether that number is a perfect number or not.

E.g. Let number is 28, factors of 28 are 1,2,4,7,14. Now the sum of all these factors are 28 itself.

Input

28

Output

Perfect Number

Input

4

Output

Not a perfect number

## C Program to identify if the number is Perfect number or not???????

### Method 1

#include <stdio.h>

int main()

{

int i,num,sum=0;

printf("Enter a number: ");

scanf("%d",&num);

for(i=1;i<num;i++)

{

if(num%i==0)

sum=sum+i;

}

if(num==sum)

printf("Perfect number");

else

printf("Not a perfect number");

return 0;

}

### Method 2

#include <stdio.h>

#include<math.h>

int main()

{

int i,num,sum=0;

printf("Enter a number: ");

scanf("%d",&num);

for(i=1;i<=sqrt(num);i++)

{

if (num%i==0)

{

if(i==1)

sum=sum+i;

else if(i==num/i)

sum=sum+i;

else

sum=sum+i+num/i;

}

}

if(num==sum)

printf("Perfect number");

else

printf("Not a perfect number");

return 0;

}

## C++ Program to identify if the number is Perfect number or not???????

### Method 1

#include <iostream>

using namespace std;

int main()

{

int i,num,sum=0;

cout<<"Enter a number: ";

cin>>num;

for(i=1;i<num;i++)

{

if(num%i==0)

sum=sum+i;

}

if(num==sum)

cout<<"Perfect number";

else

cout<<"Not a perfect number";

return 0;

}

### Method 2

#include <iostream>

#include<math.h>

using namespace std;

int main()

{

int i,num,sum=0;

cout<<"Enter a number: ";

cin>>num;

for(i=1;i<=sqrt(num);i++)

{

if (num%i==0)

{

if(i==1)

sum=sum+i;

else if(i==num/i)

sum=sum+i;

else

sum=sum+i+num/i;

}

}

if(num==sum)

cout<<"Perfect number";

else

cout<<"Not a perfect number";

return 0;

}

## Java Program to identify if the number is Perfect number or not

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

Scanner sc=new Scanner(System.in);

System.out.print("Enter a number: ");

int num=sc.nextInt();

int sum=0;

for(int i=1;i<num;i++)

{

if(num%i==0)

sum=sum+i;

}

if(sum==num)

System.out.println("Perfect Number");

else

System.out.println("Not an Perfect Number");

}

}

## Python Program to identify if the number is Perfect number or not

num=int(input("Enter a number: "))

Sum=0

for i in range(1,num):

if num%i==0:

Sum=Sum+i

if(Sum==num):

print("Perfect Number")

else:

print("Not a perfect number")

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