Description
Get a string as the input from the user and print the non-repeating characters in a string.
Input Non-repeating characters
Hello
Output
H e o
C Program
#include <stdio.h>
int main()
{
char str[20];
int i;
int frequency[256] = {0};
printf("Enter a string: ");
gets(str);
for(i = 0; str[i] != '\0'; i++)
{
frequency[str[i]]++;
}
printf("Non repeating characters: ");
for(i = 0; i < 256; i++)
{
if(frequency[i] == 1)
{
printf("%c ", i);
}
}
return 0;
}
C++ Program
#include <iostream>
#include<string.h>
using namespace std;
int main()
{
char str[20];
int i;
int frequency[256] = {0};
cout<<"Enter a string: ";
gets(str);
for(i = 0; str[i] != '\0'; i++)
{
frequency[str[i]]++;
}
cout<<"Non repeating characters: ";
for(i = 0; i < 256; i++)
{
if(frequency[i] == 1)
{
printf("%c ", i);
}
}
return 0;
}
Java
import java.util.Scanner;
public class Main
{
public static void main(String[] args) {
Scanner sc = new Scanner (System.in);
System.out.println ("Enter a string");
String str = sc.next ();
int frequency[] = new int[256];
for (int i = 0; i < str.length (); i++)
frequency[str.charAt(i)]++;
System.out.println ("Non repeating characters are: ");
for (int i = 0; i < 256; i++)
if (frequency[i] == 1)
System.out.print ((char) i + " ");
}
}
Python
Str = input('Enter a string: ')
for i in Str:
count = 0
for j in Str:
if i == j:
count+=1
if count > 1:
break
if count == 1:
print(i,end = " ")
