Description
Given an integer array of size N, write a program to reverse the array;
Sample input 1:
4
2 4 1 3
Sample output 1:
3 1 4 2
Sample input 2:
5
1 5 7 5 3
Sample output 2:
3 5 7 5 1
C Program
#include <stdio.h>
#include <limits.h>
void Reverse(int *arr, int n)
{
int temp;
for(int i = 0 ; i<n/2 ; i++)
{
temp = arr[i];
arr[i] = arr[n-1-i];
arr[n-1-i] = temp;
}
}
int main()
{
int n; scanf("%d",&n);
int arr[n];
for(int i = 0 ; i<n ; i++)
{
scanf("%d",&arr[i]);
}
Reverse(arr,n);
for(int i = 0 ; i<n ; i++)
{
printf("%d ",arr[i]);
}
return 0;
}
C++ Program
#include <bits/stdc++.h>
using namespace std;
int main()
{
int n; cin>>n;
int arr[n];
for(int i = 0 ; i<n ; i++)
{
cin>>arr[i];
}
reverse(arr,arr+n);
for(int i = 0 ; i<n ; i++)
{
cout<<arr[i]<<" ";
}
return 0;
}
JAVA Program
import java.util.*;
class Main
{
static void Reverse(int arr[], int n)
{
int temp;
for(int i = 0 ; i<n/2 ; i++)
{
temp = arr[i];
arr[i] = arr[n-1-i];
arr[n-1-i] = temp;
}
}
public static void main(String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
int arr[] = new int[n];
for(int i = 0 ; i<n ; i++)
{
arr[i] = sc.nextInt();
}
Reverse(arr,n);
for(int i = 0 ; i<n ; i++)
{
System.out.print(arr[i] + " ");
}
}
}
PYTHON Program
n = int(input())
arr = list(map(int,input().split(' ')))
arr.reverse()
print(arr)
