Description
Get an array as input from the user and then count the number of even and odd elements present in the array.
Input
Enter size of array
4
Enter the elements:
1 3 4 5
Output
Number of even elements: 1
Number of odd elements: 3
C Program
#include<stdio.h>
int main(){
int n;
int arr[n];
printf("Enter the size of array elements: ");
scanf("%d",&n);
printf("Enter the array elements: ");
for(int i=0;i<n;i++)
scanf("%d",&arr[i]);
int even=0, odd=0;
for(int i=0; i<n; i++){
if(arr[i]%2==0)
even++;
else
odd++;
}
printf("Number of even elements: %d \nNumber of odd elements: %d", even, odd);
}
C++ Program
#include<iostream>
using namespace std;
int main(){
int n;
cout<<"Enter the size of array elements: ";
cin>>n;
int arr[n];
cout<<"Enter the array elements: ";
for(int i=0;i<n;i++)
cin>>arr[i];
int even=0, odd=0;
for(int i=0; i<n; i++){
if(arr[i]%2==0)
even++;
else
odd++;
}
cout<<"Number of even elements: "<<even<< "\nNumber of odd elements: "<<odd;
}
Java Program
import java.util.Scanner;
class Main{
public static void main (String[] args)
{
int n;
Scanner sc = new Scanner(System.in);
System.out.println("Enter the size of the array: ");
n = sc.nextInt();
int[]arr = new int[n];
System.out.println("Enter the array elements: ");
for(int i = 0; i < n; i++)
{
arr[i] = sc.nextInt();
}
int even = 0, odd = 0;
for(int i=0; i<n; i++){
if((arr[i] % 2 )== 0)
even += 1;
else
odd += 1;
}
System.out.println("Number of even elements: "+ even);
System.out.println("Number of odd elements: "+ odd);
}
}
Python Program
n = int(input("Enter size of array: "))
arr = []
print("Enter array elements: ")
for i in range(0,n):
temp = int(input())
arr.append(temp)
even = 0
odd = 0
for i in range(0, n):
if arr[i]%2==0 :
even += 1
else:
odd += 1
print("Number of even elements: ",even )
print("Number of odd elements: ",odd)
