Description
Get an array as input from the user and check the type of the array, whether it is odd, even or mixed type.
Input
Enter size of array:
3
Enter elements
1 3 5
Output
Odd
C Program
#include<stdio.h>
int main()
{
int n;
printf("Enter the size of the array: ");
scanf("%d",&n);
int arr[n];
int i;
int o=0, e=0;
printf("Enter the array elements: ");
for(i = 0; i < n; i++)
{
scanf("%d",&arr[i]);
}
for(i = 0; i < n; i++)
{
if(arr[i] % 2 == 1)
o++;
if(arr[i] % 2 == 0)
e++;
}
if(o == n)
printf("Odd");
else if(e == n)
printf("Even");
else
printf("Mixed");
return 0;
}
C++ Program
#include<iostream>
using namespace std;
int main()
{
int n;
cout<<"Enter the size of the array: ";
cin>>n;
int arr[n];
int i;
int o=0, e=0;
cout<<"Enter the array elements: ";
for(i = 0; i < n; i++)
{
cin>>arr[i];
}
for(i = 0; i < n; i++)
{
if(arr[i] % 2 == 1)
o++;
if(arr[i] % 2 == 0)
e++;
}
if(o == n)
cout<<"Odd";
else if(e == n)
cout<<"Even";
else
cout<<"Mixed";
return 0;
}
Java Program
import java.util.*;
public class Main
{
public static void main(String[] args)
{
int n;
Scanner sc = new Scanner(System.in);
System.out.println("Enter the size of the array: ");
n = sc.nextInt();
int[]arr = new int[n];
System.out.println("Enter the array elements: ");
for(int i = 0; i < n; i++)
{
arr[i] = sc.nextInt();
}
int o =0, e = 0;
for(int i = 0; i < n; i++)
{
if(arr[i] % 2 == 1)
o++;
else
e++;
}
if(o == n)
System.out.print("Odd");
else if(e == n)
System.out.print("Even");
else
System.out.print("Mixed");
}
}
Python Program
n = int(input("Enter size of array: "))
arr = []
print("Enter array elements: ")
for i in range(0,n):
temp = int(input())
arr.append(temp)
o = 0
e = 0
for i in range(0,n):
if(arr[i] % 2 == 1):
o = o + 1
else:
e = e + 1
if(o == n):
print("Odd")
elif(e == n):
print("Even")
else:
print("Mixed");
