Program to find the array type

06 May 2024

C Program to find the array type

Description about Program to find the array type

Get an array as input from the user and check the type of the array, whether it is odd, even or mixed type.

Input

Enter size of array:

Enter elements

1 3 5

Output

Odd

C Program to find the array type

#include<stdio.h>

int main()

{

int n;

printf("Enter the size of the array: ");

scanf("%d",&n);

int arr[n];

int i;

int o=0, e=0;

printf("Enter the array elements: ");

for(i = 0; i < n; i++)

{

scanf("%d",&arr[i]);

}

for(i = 0; i < n; i++)

{

if(arr[i] % 2 == 1)

o++;

if(arr[i] % 2 == 0)

e++;

}

if(o == n)

printf("Odd");

else if(e == n)

printf("Even");

else

printf("Mixed");

return 0;

}

C++ Program to find the array type

#include<iostream>

using namespace std;

int main()

{

int n;

cout<<"Enter the size of the array: ";

cin>>n;

int arr[n];

int i;

int o=0, e=0;

cout<<"Enter the array elements: ";

for(i = 0; i < n; i++)

{

cin>>arr[i];

}

for(i = 0; i < n; i++)

{

if(arr[i] % 2 == 1)

o++;

if(arr[i] % 2 == 0)

e++;

}

if(o == n)

cout<<"Odd";

else if(e == n)

cout<<"Even";

else

cout<<"Mixed";

return 0;

}

Java Program to find the array type

import java.util.*;

public class Main

{

public static void main(String[] args)

{

int n;

Scanner sc = new Scanner(System.in);

System.out.println("Enter the size of the array: ");

n = sc.nextInt();

int[]arr = new int[n];

System.out.println("Enter the array elements: ");

for(int i = 0; i < n; i++)

{

arr[i] = sc.nextInt();

}

int o =0, e = 0;

for(int i = 0; i < n; i++)

{

if(arr[i] % 2 == 1)

o++;

else

e++;

}

if(o == n)

System.out.print("Odd");

else if(e == n)

System.out.print("Even");

else

System.out.print("Mixed");

}

Python Program to find the array type

n = int(input("Enter size of array: "))

arr = []

print("Enter array elements: ")

for i in range(0,n):

temp = int(input())

arr.append(temp)

o = 0

e = 0

for i in range(0,n):

if(arr[i] % 2 == 1):

o = o + 1

else:

e = e + 1

if(o == n):

print("Odd")

elif(e == n):

print("Even")

else:

print("Mixed");

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