Description
Sample input 1:
4
2 -4 -1 -3
3
1 3 5
Sample output 1:
Disjoint
Sample input 2:
5
1 5 -7 6 3
4
2 4 6 8
Sample output 2:
Not disjoint. ( 6 is common)
Solution:
C Program
#include<stdio.h>
int DisjointOrNot(int *arr1, int *arr2, int n1, int n2)
{
int flag = 1;
for (int i=0; i<n1; i++)
{
for (int j=0; j<n2; j++)
{
if (arr1[i] == arr2[j])
{
flag = 0;;
}
}
if(flag == 0)
{
break;
}
}
return flag;
}
int main()
{
int n1,n2;
scanf("%d",&n1);
int arr1[n1];
for(int i = 0 ; i<n1 ; i++)
{
scanf("%d",&arr1[i]);
}
scanf("%d",&n2);
int arr2[n2];
for(int i = 0 ; i<n2 ; i++)
{
scanf("%d",&arr2[i]);
}
if(DisjointOrNot(arr1,arr2,n1,n2) == 1)
{
printf("Disjoint");
}
else
{
printf("Not disjoint");
}
return 0;
}
C++ Program
#include<bits/stdc++.h>
using namespace std;
bool DisjointOrNot(int arr1[], int arr2[], int n1, int n2)
{
bool flag = true;
for (int i=0; i<n1; i++)
{
for (int j=0; j<n2; j++)
{
if (arr1[i] == arr2[j])
{
flag = false;;
}
}
if(flag == false)
{
break;
}
}
return flag;
}
int main()
{
int n1,n2;
cin>>n1;
int arr1[n1];
for(int i = 0 ; i<n1 ; i++)
{
cin>>arr1[i];
}
cin>>n2;
int arr2[n2];
for(int i = 0 ; i<n2 ; i++)
{
cin>>arr2[i];
}
if(DisjointOrNot(arr1,arr2,n1,n2))
{
cout<<"Disjoint";
}
else
{
cout<<"Not disjoint";
}
return 0;
}
JAVA Program
import java.util.*;
class Main
{
static boolean DisjointOrNot(int arr1[], int arr2[], int n1, int n2)
{
boolean flag = true;
for (int i=0; i<n1; i++)
{
for (int j=0; j<n2; j++)
{
if (arr1[i] == arr2[j])
{
flag = false;;
}
}
if(flag == false)
{
break;
}
}
return flag;
}
public static void main(String[] args) throws java.lang.Exception
{
Scanner sc = new Scanner(System.in);
int n1 = sc.nextInt();
int arr1[] = new int[n1];
for(int i = 0 ; i<n1 ; i++)
{
arr1[i] = sc.nextInt();
}
int n2 = sc.nextInt();
int arr2[] = new int[n2];
for(int i = 0 ; i<n2 ; i++)
{
arr2[i] = sc.nextInt();
}
if(DisjointOrNot(arr1,arr2,n1,n2)==true)
{
System.out.print("Disjoint");
}
else
{
System.out.print("Not disjoint");
}
}
}
PYTHON Program
def DisjointOrNot(arr1,arr2,n1,n2):
flag = True;
for i in range(0,n1):
for j in range(0,n2):
if arr1[i] == arr2[j] :
flag = False
if flag == False :
break
return flag
n1 = int(input())
arr1 = list(map(int,input().split(' ')))
n2 = int(input())
arr2 = list(map(int,input().split(' ')))
if DisjointOrNot(arr1,arr2,n1,n2) == True :
print("Disjoint")
else:
print("Not disjoint")
