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Program to find whether Arrays are disjoint or not

06 May 2024

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Description

Sample input 1:

4

2 -4 -1 -3

3

1 3 5

Sample output 1:

Disjoint

Sample input 2:

5

1 5 -7 6 3

4

2 4 6 8

Sample output 2:

Not disjoint. ( 6 is common)

 

Solution:

C Program

#include<stdio.h>

 

int DisjointOrNot(int *arr1, int *arr2, int n1, int n2)

{

    int flag = 1;

    for (int i=0; i<n1; i++)

    {

        for (int j=0; j<n2; j++)

        {

            if (arr1[i] == arr2[j])

            {

                flag = 0;;

            }

        }

        if(flag == 0)

        {

            break;

        }

    }

    return flag;

}

 

int main()

{

       int n1,n2;

       scanf("%d",&n1);

       int arr1[n1];

       for(int i = 0 ; i<n1 ; i++)

       {

               scanf("%d",&arr1[i]);

       }

       scanf("%d",&n2);

       int arr2[n2];

       for(int i = 0 ; i<n2 ; i++)

       {

               scanf("%d",&arr2[i]);

       }

       if(DisjointOrNot(arr1,arr2,n1,n2) == 1)

       {

           printf("Disjoint");

       }

       else

       {

           printf("Not disjoint");

       }

       return 0;

}

 

C++ Program

#include<bits/stdc++.h>

using namespace std;

 

bool DisjointOrNot(int arr1[], int arr2[], int n1, int n2)

{

    bool flag = true;

    for (int i=0; i<n1; i++)

    {

        for (int j=0; j<n2; j++)

        {

            if (arr1[i] == arr2[j])

            {

                flag = false;;

            }

        }

        if(flag == false)

        {

            break;

        }

    }

    return flag;

}

 

int main()

{

       int n1,n2;

       cin>>n1;

       int arr1[n1];

       for(int i = 0 ; i<n1 ; i++)

       {

               cin>>arr1[i];

       }

       cin>>n2;

       int arr2[n2];

       for(int i = 0 ; i<n2 ; i++)

       {

               cin>>arr2[i];

       }

       if(DisjointOrNot(arr1,arr2,n1,n2))

       {

           cout<<"Disjoint";

       }

       else

       {

           cout<<"Not disjoint";

       }

       return 0;

}

 

JAVA Program

import java.util.*;

class Main

{

   static boolean DisjointOrNot(int arr1[], int arr2[], int n1, int n2)

    {

        boolean flag = true;

        for (int i=0; i<n1; i++)

        {

            for (int j=0; j<n2; j++)

            {

                if (arr1[i] == arr2[j])

                {

                    flag = false;;

                }

            }

            if(flag == false)

            {

                break;

            }

        }

        return flag;

    }

  

       public static void main(String[] args) throws java.lang.Exception

       {

               Scanner sc = new Scanner(System.in);

               int n1 = sc.nextInt();

               int arr1[] = new int[n1];

               for(int i = 0 ; i<n1 ; i++)

               {

                             arr1[i] = sc.nextInt();

               }

               int n2 = sc.nextInt();

               int arr2[] = new int[n2];

               for(int i = 0 ; i<n2 ; i++)

               {

                             arr2[i] = sc.nextInt();

               }

               if(DisjointOrNot(arr1,arr2,n1,n2)==true)

           {

               System.out.print("Disjoint");

           }

           else

           {

               System.out.print("Not disjoint");

           }

       }

}

 

PYTHON Program

def DisjointOrNot(arr1,arr2,n1,n2):

    flag = True;

    for i in range(0,n1):

        for j in range(0,n2):

            if arr1[i] == arr2[j] :

                flag = False

        if flag == False :

            break

    return flag

 

n1 = int(input())

arr1 = list(map(int,input().split(' ')))

n2 = int(input())

arr2 = list(map(int,input().split(' ')))

if DisjointOrNot(arr1,arr2,n1,n2) == True :

    print("Disjoint")

else:

    print("Not disjoint")

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