Cognizant Qunatitative Ability Questions
A.2 log 6 + 1
B.6 log 2 + 1
C.2 log 6 + 2
D.6 log 2 +2
A.1
B.2
C.3
D.4
Explanation: log4 √(a + b + c) = log4 √(4 + 5 + 7) = = log4 √16 == log4 4 = 1
A. 100
B. 110
C. 120
D. 130
Explanation: LCM of 20,30 and 40 = 120
HCF of 20,30 and 40 = 10
Difference between L.C.M and H.C.F is 120-10 = 110.
A.6
B.24
C.120
D.720
Explanation: six different books on a shell can be arranged in 6P6 6! Ways = 720 ways
A. 26.66%
B. 12%
C. 30%
D. 13.33%
Explanation: Let principal be rs. p
Then simple interest after 15 years will be 2p
Now, Simple Interest = Principal × Rate × Time
2p = p × Rate × 15
2 = Rate × 15
Rate × 15 = 2
Rate = 2/15
rate = 0.1333
So, rate of interest = 13.33%
A. 20
B. 25
C. 24
D. 21
Explanation: The largest power of 20 contained in 100 factorials.
20=5×2×2
The highest prime factor 20 is 5.
So, number of powers of 20 will only depend on power of 5.
Also, 1005=20,10025=4.
Therefore, the power of 5 is 20+4=24
Hence, the largest power of 20 contained in 100 factorial is 24.
A. 20 km
B. 21 km
C. 29 km
D. 30 km
Explanation: The distance travelled by Rajesh from home to office by metro train = 4/5
The distance travelled by auto = 3/20
The distance travelled on Foot = 1 km
Let x be the total distance from the home to the office
Distance travelled
x = [(4/5)x + (3/20)x] + 1
x [1 – (4/5) – (3/20)] =1
x (1/20)=1
x = 20 km
Thus, the total distance travelled by Rajesh from home to the office is 20 km.
A. 1600
B. 3600
C. 14400
D. 32400
Explanation: The LCM is 120
Now to find the smallest square number divisible by 120:
Factors of 120 = 2*2*2*3*5
Now, to form pairs, you have to multiply it by 2*3*5 or 30
120*30 = 3600
Hence, the smallest perfect square number that is divisible by 24, 30, and 60? is 3600 (it is the square of 60).
A. 15
B. 10
C. 5
D. 8
Explanation: Let the no. of hen be H1, no. of eggs E1, no. days D1 separately
Thus,
H1=50, E1=200, D1= 2
We are supposed to find what amount of time will 20 hens require to give 400 eggs
Allow x to be the no. of days
So,
H2= 20, E2= 400, D2=x
Therefore, the formula here will be
(H1 * D1)/E1 = (H2 * D2)/ E2
(50 * 2)/200 = (20 * x)/400
(50 * 2) * 400/(200 * 20) = x
Hence, x = 10
So, we can conclude that 20 hens will take 10 days to lay 400 eggs.
Consequently 20 hens require 10 days to give 400 eggs.
A. Rs. 1829
B. Rs. 1632
C. Rs. 1923
D. Rs. 2020
A. 21, 35
B. 35, 49
C. 49, 63
D. 63, 77
Explanation: Going through option verification
Option A – 21 and 35 , L.C.M =105 , Hence wrong option
Option b – 35 and 49 , L.C.M =245 , Hence wrong option
Option c – 49 and 63, L.C.M =441 , and H.C.F is 7 and difference between numbers is 14, hence option C
A. Rs. 6,25,000
B. Rs. 6,50,000
C. Rs. 6,75,000
D. Rs. 6,37,000
Explanation: cp = x
Sold at Rs. 50000 less than Rs. x
so, sp = x - 50000
Also, 50000 is 8% of x
so, 50000 = 8/100 of x
or, 50000 = 0.08x
or, x = 50000/0.08 = 625000
So, Piya bought at Rs. 625000.
To gain what she lost in her first transaction I.e., Rs 50000 she should have sold the car at
Rs. 625000 + 50000 = Rs. 6,75,000
A. 12, 2
B. 24, 4
C. 36, 6
D. 48, 8
Explanation: The permutations and combinations of abcd taken 3 at a time are respectively 4P3 and 4C3
4P3 = 4! /1! = 24
4C3 = 4!/3! = 4
A. 34
B. 23
C. 30
D. 40
Explanation: Average = sum of elements / no. of elements.
average age of cricket team = sum of ages of players/ no of players
22 = sum of ages of players/ no of players
22 × 11 = sum of ages of players
242 = sum of ages of players
as average age gets increased by 1 year when the coach age is also included
23 = sum of ages of players + age of coach / no of players + 1
23 ( 11 + 1 ) = sum of ages of players + age of coach
23 × 12 = sum of ages of players + age of coach
276 = sum of ages of players + age of coach
Now,
age of coach = sum of ages of players + age of coach - sum of ages of players
age of coach = 276 – 242= 34
Hence, the age of the coach is 34
A. 21
B. 42
C. 24
D. 40
Explanation: 16,800 = 168 * 100 = 25 * 7 *3 *52 =2* 24 * 7 *3 *52, hence 2,7 and 3 are the one’s which are not perfect squares , hence the product of 2*3*7 = 42 should be divided