Description about the Program to calculate Maximum number of handshakes
Get the number of people in the room as input from the user. Then calculate the maximum number of handshakes possible among that people.
For e.g.
If there are N people in the room then the first person has to shake hand with N-1 people and second person has to shake hand with N-1-1 people i.e., N-2 handshakes are possible. Thus, it goes on.
So total hand shakes = N-1 + N-2 + N-3 +………+1 + 0
Input
10
Output
45
C Program to calculate Maximum number of handshakes
#include <stdio.h>
int main()
{
int num;
printf("Enter the number of people in the room: ");
scanf("%d",&num);
int total = num * (num-1) / 2;
printf("Total handshakes = %d",total);
return 0;
}
C++ Program to calculate Maximum number of handshakes
#include <iostream>
using namespace std;
int main()
{
int num;
cout<<"Enter the number of people in the room: ";
cin>>num;
int total = num * (num-1) / 2;
cout<<"Total handshakes = "<<total;
return 0;
}
Java Program to calculate Maximum number of handshakes
import java.util.Scanner;
public class Main
{
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
System.out.print("Enter the number of people in the room: ");
int num = sc.nextInt();
int total = num * (num-1) / 2;
System.out.println("Total number of handshakes = "+total);
}
}
Python Program to calculate Maximum number of handshakes
num= int(input("Enter the number of people in the room: "))
total = int(num * ((num - 1) / 2))
print("Total number of handshakes = ",total)
