Description
Get a number as input from the user and check within that number how many numbers are there with exactly 9 divisors.
Input
40
Output
1
C Program
#include <stdio.h>
int numberOfDivisors(int num)
{
int c=0;
for(int i=1;i<=num;i++)
{
if(num%i==0)
c +=1;
}
return c;
}
int countNumbers(int n)
{
int c=0;
for(int i=1;i<=n;i++)
{
if(numberOfDivisors(i)==9)
c += 1;
}
return c;
}
int main()
{
int num;
printf("Enter the number: ");
scanf("%d",&num);
printf("%d",countNumbers(num));
return 0;
}
C++ Program
#include <iostream>
using namespace std;
int numberOfDivisors(int num)
{
int c=0;
for(int i=1;i<=num;i++)
{
if(num%i==0)
c +=1;
}
return c;
}
int countNumbers(int n)
{
int c=0;
for(int i=1;i<=n;i++)
{
if(numberOfDivisors(i)==9)
c += 1;
}
return c;
}
int main()
{
int num;
cout<<"Enter the number: ";
cin>>num;
cout<<countNumbers(num);
return 0;
}
Java Program
import java.util.Scanner;
public class Main
{
static int numberOfDivisors(int num)
{
int c=0;
for(int i=1;i<=num;i++)
{
if(num%i==0)
c +=1;
}
return c;
}
static int countNumbers(int n)
{
int c=0;
for(int i=1;i<=n;i++)
{
if(numberOfDivisors(i)==9)
c += 1;
}
return c;
}
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter a number: ");
int num=sc.nextInt();
System.out.println(countNumbers(num));
}
}
Python Program
def numberOfDivisors(n):
c=0
for i in range(1,n+1):
if n%i==0:
c=c+1
return c
def countNumbers(n):
c=0
for i in range(1,n+1):
if(numberOfDivisors(i)==9):
c=c+1
return c
num=int(input("Enter a number: "))
print(countNumbers(num))
