Description
Given an N x M matrix, Write a program to print the max elements in all the rows.
Sample input :
3 3
1 2 3
6 5 4
12 30 1
Sample output :
3
6
30
C Program
#include <stdio.h>
int main()
{
int r,c;
scanf("%d%d",&r,&c);
int mat[r]c];
for(int i = 0 ; i<r ; i++){
for(int j = 0 ; j<c ; j++){
scanf("%d",&mat[i][j]) ;
}
}
int max;
for(int i = 0 ; i<r ; i++){
max = mat[i][0];
for(int j = 1 ; j<c ; j++){
if(mat[i][j] > max){
max = mat[i][j];
}
}
printf("%d\n",max);
}
return 0;
}
C++ Program
#include <bits/stdc++.h>
using namespace std;
int main()
{
int r,c;
cin>>r>>c;
int mat[r]c];
for(int i = 0 ; i<r ; i++){
for(int j = 0 ; j<c ; j++){
cin>>mat[i][j] ;
}
}
int max;
for(int i = 0 ; i<r ; i++){
max = mat[i][0];
for(int j = 1 ; j<c ; j++){
if(mat[i][j] > max){
max = mat[i][j];
}
}
cout<<mat[i][j];
}
return 0;
}
JAVA Program
import java.util.*;
import java.lang.*;
import java.io.*;
class Ideone
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner sc=new Scanner(System.in);
int r = sc.nextInt();
int c = sc.nextInt();
int mat[][] = new int[r][c];
for(int i = 0 ; i<r ; i++){
for(int j = 0 ; j<c ; j++){
mat[i][j] = sc.nextInt();
}
}
int max;
for(int i = 0 ; i<r ; i++){
max = mat[i][0];
for(int j = 1 ; j<c ; j++){
if(mat[i][j] > max){
max = mat[i][j];
}
}
System.out.println(max);
}
}
}
PYTHON Program
def MaxRowElement(a):
for i in range(0,len(a)):
m = 0
for j in range(0,len(a[0])):
if a[i][j] > m :
m = a[i][j]
print(m)
a = [[1, 2, 3],
[4, 5, 6],
[7, 8, 9],]
MaxRowElement(a)
