Tech Mahindra Quantitative Ability Questions
A. Rs. 293.70
B. Rs. 299.9
C. Rs. 240.5
D. Rs. 297.50
Explanation:
Cost price of the article= Rs. 300
Selling price of the article to the customer=(100-11) % of cost price of article.
= (89/100) ×300=267.
Now the cost price of the article for the customer is Rs. 267
Customer makes a profit of 10%.
Selling price of the article by the customer to his friend is (110/100) ×267=293.7
Therefore, the customer sells the article at Rs. 293.7 to his friend.
A.17.5%
B.20 %
C.25 %
D.15 %
A.12
B.15
C.13
D.14
E.16
A.114
B.100
C.85
D.95
Explanation: Let's say, no. of coins of 10 cents = x
No. of coins of 20 cents = 1.7x
No. of coins of one dollar = 0.7x
One dollar is equal to 100 cents i.e., 10 cents = 0.1 dollar
0.1*x+0.2*1.7x+1*0.7x = $57
1.14*x = 57
X = 50
No. of coins of 20 cents = 1.7*x
=1.7*50
=85
A.6.5
B.8
C.6
D.8.5
Explanation: Average of five quantities = 6.
Then, sum of five quantities = 30.
Average of two of them is 3, then sum of two of them is 6.
From the above statement, sum of the remaining three quantities = 24.
Then, average of the remaining three quantities = 24/3 = 8.
A. 5.75
B. 6.75
C. 3.75
D. 4.75
Explanation: let Raja buys ‘x’ apples at rate four for a rupee and ‘x’ apples at three for a rupee.
So, cost price = x/4 + x/3
Question is asking about 6 apples
Then, CP = 6/4 + 6/3 = 3.5
Now SP = (125/100) *3.5 = 4.75
Therefore, Raja should sell 6 apples for 4.75
A. 50%
B. 60%
C. 30%
D. 40%
Explanation: Let the labelled price is 100.
Prasanth bought it for 75 after getting a 25% discount.
Now he sells the article at (120/100) *100 = 120.
So % profit he earns = (45/75) *100 = 60%
A. 12%
B. 10%
C. 28%
D. 19%
Explanation: This question can be solved through option verification,
First option – 12%
After first increment, 100 + 12%100 = 112
Then second increment, 112 + 12%112 = 125.44
Then last which is third increment, 125.44 + 12%125.44 = 140.49, which is not satisfying the condition of increasing to 133.1 after three successive increments.
Similarly, Second option – 10%
After first increment, 100 + 10%100 = 110
Then second increment, 110 + 10%110 = 121
Then last which is third increment, 121 + 10%121 = 133.1, which satisfies the given condition. So, option B is the answer.
A. 17.5 liters
B. 18 liters
C. 19 liters
D. 20 liters
A. 50
B. 40
C. 100
D. 150
Explanation: W = m × d
m1 × d1 = m2 × d2
Where -
m1 = Initial men
d1 = Initial days
m2 = Final men
d2 = Final days
Thus,
25 × 20 = 5 × d2
d2 = 25 × 20/5
d2 = 5 × 20
= 100
A. 3 seconds
B. 6 seconds
C. 11 seconds
D. 12 seconds
Explanation: Height above sea level at which the aircraft flies = 240 m
Depth below sea level at which the submarine is lying = 420m
Average speed with which the bomb falls down = 60 m/s
Total distance the bomb falls to strike the submarine = 240 +420 = 660m
As we know,
Time = Distance/speed = 660/60 = 11 seconds.
A. Rs. 3,350.50
B. Rs. 3,212.50
C. Rs. 3,412.50
D. Rs. 3,550.50
Explanation: The total cost for the year = 250000 + 2% of 2500000 + 2000
= Rs. 257000
For getting return of 15% he must earn = (257000×15)/100
= Rs. 38550 per year
Then, Monthly Rent = 38550/12
= Rs. 3212.5
A. 5 : 1
B. 6 : 1
C. 7 : 1
D. 1 : 7
Explanation: Given Father’s age = 35 years
And Son’s age = 5 years
Then, ratio of father’s age to the son’s age = 35 : 5 = 7 : 1
A. 1 year
B. 2 years
C. 6 months
D. 9 months
Explanation: Total age of the family three years ago = 17 x 5 = 85 years.
Let the present age of the child be x years.
Present total age of the family = 85 + 5 x 3 + x = (100 + x) years.
Given (100+x)/? 66 =,17
100+x=102
x=2 years
A. $65,000
B. $70,000
C. $75,000
D. $80,000
Explanation: A = P (1 + R/100) n
A = $84,364.80
P = ?
R = 4
n = 3
84,364.80 = P (1 + 4/100) ³
84,364.80 = P (1.04) ³
84,364.80 = P (1.124864)
P = $75,000
